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2016 NECO GCE PHYSICS PRACTICAL QUESTION AND ANSWERS NOW AVAILABLE FOR FREE
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EDUBRAZEE 07:12 Wed, 02 Nov 2016

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THUR 3rd November 2016
PHYSICS(Alt to practical)2:00pm-4:45Pm











(1a)
PLS DRAW A TABLE:

i|Mi(cm)|Mi(g)|Li(cm)(Raw)|Li(cm)(Real)|e=li-lo:
1|4.75 |47.50 |2.60|5.20 |1.40|
2|6.13 |61.30 |3.15|6.30 |2.50|
3|8.53 |85.80 |3.72|7.40 |3.60|
4|10.43|104.30|4.30|8.60 |4.80|
5|12.28|122.80|4.85|9.70 |5.90|
6|14.20|142.00|5.40|10.80|7.00|


Slope= De(cm)/DM(g) = e2-e1/M2-M1


(1aviii)
-I avoided parallex error when taking the reading
-I would ensure that the masses do not touch the ground.
-I would ensure that the support is rigid

(1bi) This means that the ratio of force to extension is 10Nm-1

(1bii) E = 1/2Ke^2
but F=ke
.:. E = F/k
E= 1/2k(F/K)^2
E=F^2/2k



===================


(3ai)
TABULATE
i|X(n)|Y(n)|V(v)|Z=V^-1|R(n)
1|2|2|1.50|0.67|1.00
2|6|3|1.30|0.77|2.00
3|12|4|1.14|0.88|3.00
4|20|5|1.00|1.00|4.00
5|30|6|0.91|1.10|5.00

Precaution:
-I will ensure tight connections of all wires
-i would ensure that the key is opened during each reading

(3bi)
R=(2*3)/(2+3)+0.8
R=1.20+0.8
R=2.0ohms
But I=E.M.F/R+r
I=E/2+r
2I+Ir=E
Ir=E-2I
r=(E-2I)/I

(3bii)
V=IR
=2.6*4
V=10.40volts





COMPLETED



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